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NEW QUESTION 36
Refer to the exhibit.
When running OSPF, what would cause router A not to form an adjacency with router B?
- A. The loopback addresses are on different subnets.
- B. Route summarization is enabled on both routers.
- C. The process identifier on router A is different than the process identifier on router B.
- D. The values of the dead timers on the routers are different.
Answer: D
Explanation:
Explanation/Reference:
To form an adjacency (become neighbor), router A & B must have the same Hello interval,
Dead interval and AREA numbers
NEW QUESTION 37
A retailer has new campaign assets for an upcoming spring collection. They want to offer an immersive post click experience that allows viewers to swipe through and took at video, photo and text formats in one ad.
Which creative format should the retailer use?
- A. Stories
- B. In stream video
- C. Reels
- D. Instant experience
Answer: D
NEW QUESTION 38
Refer to the exhibit.
A network has been planned as shown. Which three statements accurately describe the areas and devices in the network plan? (Choose three.)
- A. Network Device A is a hub.
- B. Network Device A is a switch.
- C. Network Device B is a hub.
- D. Area 2 contains a Layer 2 device.
- E. Area 1 contains a Layer 2 device.
- F. Network Device B is a switch.
Answer: B,C,E
Explanation:
Switches use a separate collision domain for each port, so device A must be a switch. Hubs, however, place all ports in the same collision domain so device B is a hub. Switches reside in layer 2 while hubs are layer 1 devices.
NEW QUESTION 39
What are two common TCP applications? (Choose two.)
- A. TFTP
- B. FTP
- C. DNS
- D. SMTP
- E. SNMP
Answer: B,D
Explanation:
SMTP uses TCP port 25, while FTP uses TCP ports 20 and 21. http://pentestlab.wordpress.com/2012/03/05/common-tcpip-ports/
NEW QUESTION 40
Which two statements describe the IP address 10.16.3.65/23? (Choose two.)
- A. The broadcast address of the subnet is 10.16.3.255 255.255.254.0.
- B. The last valid host address in the subnet is 10.16.2.254 255.255.254.0
- C. The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
- D. The subnet address is 10.16.3.0 255.255.254.0.
- E. The network is not subnetted.
Answer: A,C
Explanation:
The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits. The block size in the third octet is 2 (256 - 254). So this makes the subnets in 0, 2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0 subnet. The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are
2.1 through 3.254
NEW QUESTION 41
……
